Yes, but don't fall for this misconception: Peak power vs. RMS power of an amplifier has absolutely
nothing to do with the peak and RMS values of the input voltage (or output voltage).
With any sine wave the ratio between the peak and the RMS value is fixed and the peak value is always 1.41 times the RMS value. You don't get a higher output wattage just because you look at the peak value instead of the RMS value. It's just a matter of how you describe one and the same signal. The peak power of an amplifier is till limited by it's maximum output voltage, not matter if you provide the peak or the RMS value.
Not much of an issue, either. These Hypex based amps are
nearly ideal voltage sources. The maximum voltage into 4 ohms is almost identical to the maximum voltage into 8 ohms loads. As a consequence, the power into 4 ohms almost doubles that into 8 ohms.
As I said before, you cannot reach these power peaks with insufficient input voltage.
This makes no difference regarding the output voltage.
Let's stick with the Audiophonics MPA-S250NC RCA for now. Max. power into 8 ohms is 150 W.
Power = voltage * current
Current = voltage / impedance
Power = voltage² / impedance
Voltage = sqrt(power * impedance)
=>
Voltage = sqrt(150 W * 8 ohms) = 34.64 V
This is an RMS value, but that doesn't matter, 34.64 Vrms are exactly the same as 49 Vpeak at the same time. No difference, just different ways to describe the same thing, no difference in output power.
The MPA-S250NC RCA needs an RMS input voltage of 1.66 Vrms (fully equivalent to 2.34 Vpeak) to generate an output voltage of 34.64 Vrms. This equals a voltage gain of 20 * log(34.64 V / 1.66 V) = 26.39 dB or in plain numbers a factor of 20.9.
You will notice that this factor is very close to that calculated by
@Aquaman for a 4 ohm load. This is because the output voltage hardly drops into 4 ohms compared to 8 ohms. But here is the essential part: If you limit the input voltage to 0.5 Vrms then the output voltage is limited to 20.9 * 0.5 Vrms = 10.45 Vrms (which is exactly the same as 14.78 Vpeak).
Power = voltage² / impedance
=>
Power = (10.45 V)² / 8 ohms =
13.65 W
13.65 W is the absolute maximum power you can get from this amp if the output voltage of the WiiM Ultra is limited to 0.5 Vrms. There is absolutely no headroom. No higher peak wattage. No nothing. There is simply no way to get more than 13.65 W out of this amp into an 8 ohm load with the Ultra set to 500 mVrms. Period.
If the true frequency dependent impedance of your 8 ohm speakers dips down into 4 ohms at any given frequency, then the maximum output power at this frequency is roughly 22 W.